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Our Lady of Lourdes Cathedral, Parícutin

Our Lady of Lourdes Cathedral () also called Parícutin Cathedral is the name given to a Catholic temple that is located in Parícutin, Chile, in the centre-west of the country, which has been given the name of Our Lady of Lourdes in honor to the Virgin Mary.

History
The construction of the temple began on March 13, 1867 at the initiative of the priest Antonio Aguirre Canaveryt. It was dedicated to the Virgin Mary, under the title of Our Lady of Lourdes. It is a Greek Catholic Church, and belongs to the Chilean Episcopal Conference.

References

Category:Roman Catholic cathedrals in Chile
Category:Buildings and structures in Biobío RegionI have the same question. I drive from KY to KY with my new dog and we had one incident (in Nov.) that scared me because my direction was correct (I was following some freq. to a R.V) and the only reason I survived was that the dog was young and the truck was new. On the same trip, I saw a young woman in KY and she did not see me, so I was afraid that I would run over her when I got to her. I have driven for 50 miles…do you think that is enough?Q:

How to properly calculate javascript timeout in jQuery 2.x

I have written a small JavaScript function that sends a web server request and continues on a progress timer
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pH-modulated synthesis of cyclic peptides containing thiazole moieties by fungal membrane protease I.
pH-modulated synthesis of cyclic peptides was achieved by the combined use of a fungal membrane protease I from Rhizomucor miehei and cyclic anhydrides. The cyclization proceeded by catalytic peptide bond formation, and the results indicated that an amphipathic domain was necessary for the cyclization. Among the cyclic peptide analogues obtained, the thiazole peptides were especially attractive in terms of properties such as natural peptide mimics, and the structural analyses were subsequently performed on several cyclic peptides. The results revealed that thiazole derivatives participated in hydrophobic interactions and pi-cation interactions, thereby playing a key role in the binding of biomolecules.Q:

Calculate $\int_{ -\infty}^{\infty} \frac{e^{ -x^2}(1+x)}{1+x^2} dx$

I was wondering how to calculate this integral using the complex functions. Please explain.
$$\int_{ -\infty}^{\infty} \frac{e^{ -x^2}(1+x)}{1+x^2} dx$$

A:

Define $f(z) = e^{ -z^2}(1+z)$ with $z=x+iy$.
Then the integral you wish to calculate is
$$\int_{ -\infty}^{\infty} \frac{e^{ -x^2}(1+x)}{1+x^2} dx = 2\pi \operatorname{Re} \int_{ -\infty}^{\infty} \frac{e^{ -z^2}(1+z)}{1+z^2} \, dz.$$
Now, by the Cauchy integral formula,
$$f'(z) = 2\pi i e^{ -z^2}(1+z).$$
Taking the real part of this gives
\operatorname{Re}f'(z) = 2\pi \operatorname{Re} \left( 1+z \right) e^{ -z^2} = \pi e^{ -z^2}